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Work done = Force x distance moved in the direction of force

So work done = 15 x 20 = 300 joule

That force 15 newton would be the necessary and equivalent force to overcome the static frictional force. Static frictional force depends, of course, on the mass of the box.

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14y ago
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14y ago

Just multiply the force times the distance, to get the work. The number of students is irrelevant - it seems that 800 Newtons is the total force.

Just multiply the force times the distance, to get the work. The number of students is irrelevant - it seems that 800 Newtons is the total force.

Just multiply the force times the distance, to get the work. The number of students is irrelevant - it seems that 800 Newtons is the total force.

Just multiply the force times the distance, to get the work. The number of students is irrelevant - it seems that 800 Newtons is the total force.

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13y ago

A force of 20 newtons acting through a distance of 40 meters produces

work equal to (20 x 40) = 800 newton-meters = 800 joules.

The weight of the cart doesn't matter.

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13y ago

A force of 20 newtons acting through a distance of 40 meters produces

work equal to (20 x 40) = 800 newton-meters = 800 joules.

The weight of the cart doesn't matter.

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14y ago

Just multiply the force times the distance, to get the work. The number of students is irrelevant - it seems that 800 Newtons is the total force.

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14y ago

800((:

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13y ago

2088j

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14y ago

2,088 J

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Q: A force of 800 newtons is needed to push a car across a lot 2 students push the car 40 meters How much total work do both students do?
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