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-18 kj/mol

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Wiki User

8y ago
This answer is:
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Artiic

Lvl 1
1y ago
Pis
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Artiic

Lvl 1
1y ago
Positive not ne
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Wiki User

12y ago

G = -18 kJ/mol

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Wiki User

9y ago

30kj

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Natalie Steger

Lvl 1
2y ago
correct!!

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Wiki User

12y ago

-170 kJ

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BlackFire Gaming

Lvl 3
2y ago

G=0kj/mol

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Wiki User

6y ago

30 kj

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How long can you stretch an ounce of gold?

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What volume of 0.500m mgoh is required to neutralize 0.200l of 0.100m hcl?

Im assuming you mean Mg(OH)2 and not MgOHThe reaction between Mg(OH)2 and HCl is as follows: Mg(OH)2 (aq) + 2HCl (aq) -> MgCl2 (aq) + 2H2O (l)First the number of mole is found: n(HCl) = c × v = 0.100M × 0.200L = 0.0200mol (to 3 significant figures)Next we find the number of mole of Mg(OH)2:n(Mg(OH)2) ÷ n(HCl) = Coefficient of Mg(OH)2 ÷ Coefficient of HCl n(Mg(OH)2) ÷ n(HCl) = 1 ÷ 2 therefore:n(Mg(OH)2) = (1 ÷ 2) × n(HCl) n(Mg(OH)2) = (1 ÷ 2) × 0.0200moln(Mg(OH)2) = 0.0100mol (to 3 significant figures)Finally we calculate the volume of Mg(OH)2 reacted:v(Mg(OH)2) = n ÷ cv(Mg(OH)2) = 0.0100mol ÷ 0.500MThereforev(Mg(OH)2) = 0.0200L (to 3 significant figures) = 20.0ml (to 3 significant figures)


How much water is in gold?

A whole lot! There is a huge quantity of gold is seawater. But it's distributed widely - across all the oceans of all the world - and is incorporated on the atomic level. That makes it very, very hard to separate out. No one has demonstrated that it can be done economically. The concentration of gold in seawater varies from place to place, and ranges between 5 to 50 ppt (about .005 to .05 tonnes (5 to 50 kg) per km3) Given that the volume of all the seas is about 1.37 billion km3 The total amount of gold in all the seas is about 7 to 75 billion kg.


Does a lemon have more citric acid than an orange?

The concentrations of citric acid in citrus fruits range from .005 mol/L for oranges and grapefruits to .030 mol/L in lemons and limes. These values will vary depending on the circumstances in which the fruit was grown. welll actually they sometimes do. it depends where they grew from. bananas