It is 1/2.
the probability is 4 out of 6
1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads
The probability of tossing a 1 or 2 on a six sided die is 2 in 6, or 1 in 3.
There are 36 possibilities when rolling two six sided die. 15 of them result in a prime number (2,3,5,7,11) So the probability is 15 in 36 or a 5 in 12 chance.
there are three distinct outcomes1,3or5. But there is no probability which will come.
The probability of tossing an odd number (assumed on a die) is 3 in 6 or 1 in 2. The probability of tossing a tail (assumed on a coin) is 1 in 2. Since these are unrelated events, and the question said "and", simply multiply the probabilities to get 1 in 4.
the probability is 4 out of 6
1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads
The probability of tossing a 1 or 2 on a six sided die is 2 in 6, or 1 in 3.
Multiply the probability by the number of times the experiment was carried out. 0.6x10=6
There are 36 possibilities when rolling two six sided die. 15 of them result in a prime number (2,3,5,7,11) So the probability is 15 in 36 or a 5 in 12 chance.
there are three distinct outcomes1,3or5. But there is no probability which will come.
It is 2/3.
-3/12
The probability of an event is the number of favourable outcomes divided by the total number of possible outcomes. What is the total number of possible outcomes of tossing a number cube? 6 How many outcomes are favourable to the event of getting a five? 1 So the prob is 1/6 or 0.16667
3/8. And the coin tossing is totally irrelevant.
The probability is 1/2 if the coin is flipped only twice. As the number of flips increases, the probability approaches 1.