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-1.6-6.2 Subtract the signed number by adding the opposite of the second number to the first?
To subtract a negative number, you must change the subtraction sign to an addition sign, then make the second number its opposite. Ex. (-9)-(-13) (-9)+(+13)=4
Yes. Choose any three consecutive counting numbers. The first number is the second number subtract 1 The third number is the second number add 1 Adding the three numbers together is the same as adding: (the second number subtract one) plus the second number plus (the second number add one). The "subtract one" and "add one" cancel each other out to leave the sum as: the second number plus the second number plus the second number Which is the same as 3 times the second number, ie the sum is a multiple of 3 and so is divisible by 3. For example: 10 + 11 + 12 = (11 - 1) + 11 + (11 + 1) = 11 - 1 + 11 + 11 + 1 = 11 + 11 + 11 + (1 - 1) = 11 + 11 + 11 + 0 = 11 + 11 + 11 = 3 x 11
Choose any number for the first number. Subtract 10 minus the number you chose to get the second number.
Multiply the first number by 3 to get the second number, subtract 5 from the second number to get the third number, multiply the third number by 3 to get the fourth number, subtract 5 from the fourth number to get the fifth number, ... So the pattern is: starting number, previous x 3, previous - 5, previous x 3, previous - 5, previous x 3
This, of course, has infinitely many solutions. Choose ANY number for the first number. Then, subtract 43 minus your first number, to get the second number.
To subtract a negative number, you must change the subtraction sign to an addition sign, then make the second number its opposite. Ex. (-9)-(-13) (-9)+(+13)=4
Yes. Choose any three consecutive counting numbers. The first number is the second number subtract 1 The third number is the second number add 1 Adding the three numbers together is the same as adding: (the second number subtract one) plus the second number plus (the second number add one). The "subtract one" and "add one" cancel each other out to leave the sum as: the second number plus the second number plus the second number Which is the same as 3 times the second number, ie the sum is a multiple of 3 and so is divisible by 3. For example: 10 + 11 + 12 = (11 - 1) + 11 + (11 + 1) = 11 - 1 + 11 + 11 + 1 = 11 + 11 + 11 + (1 - 1) = 11 + 11 + 11 + 0 = 11 + 11 + 11 = 3 x 11
It´s like adding them. You pretend that the second number is a positive number and then you add the two numbers together. For example: (-7) - (-2) = -7 + 2 = -5 (-2) - (-7) = -2 + 7 = 5
It is not clear what you mean by "oppisites" or even opposite. Often a number is the opposite of its opposite. So if the first is greater than the second, the second, which is the opposite of the first, is smaller than the first.
depends if the first number is bigger than the second number than it is a negative
It can be if the first number is x + 21 and the second is x for any number x.
The same way you'd add any other negative numbers. Adding a negative is the same as subtracting, and subtracting a negative is the same as adding. (-2) + (-2) = (-4) (-2) - (-2) = 0 you are wrong if you add or subtract two negitives its always a positive dont you know your math. And the second problem you have is wrong to because when you subtract two negitives you change the sign of the secong number to positive and you change the subtraction sign to a addition sign.
12
Choose any number for the first number. Subtract 10 minus the number you chose to get the second number.
you take the last digit in the first one and add/subtract it to the last digit in the second one and that is your answer
There are infinitely many solutions for that. Choose ANY number as the first number. The subtract 100 minus this number, to get the second number.
No.