3 numbers whose product is about 9000?

Answer 1

Prime factorisation of 9000 = 2*2*2*3*3*5*5*5

Well 9000 can be expressed as the product of (2*2*2)*(3*3)*(5*5*5) or 8*9*125

So, 9000 can be expressed as the product of 8,9 and 125.

It can be expressed as 2*(2*2*5*5)*(3*3*5)

i.e. 9000 = 2*100*45

By using the method of Prime factorisation, we can find many cases in which product of 3 numbers is 9000.

We can also express it as 900*(1/10)*100, which cannot be done using P.F. of 9000.

We can find a large number of cases in which product of three numbers is 9000.

We can find numbers by this method:

Assume any three variables and put their product equal to 9000

i.e. x*y*z = 9000 where x,y and z are real numbers.

Put any value of x, say 34 and any value of y, say 23, then on putting the values we can find the value of z i.e. 34*23*z = 9000

782*z = 9000

z = 11.5089

So, this method works better than Prime Factorisation.

Answer 2

21