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A = 2b + c
Subtract 'c' from each side:
A - c = 2b
Divide each side by 2:
b = 1/2 (A - c)
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∙ 13y ago
Anonymous
2a+2b=c
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Which of these formulas is rewritten form the original formula to solve for b a equals 2b plus c?
b= 1/2 (a - c)
If b equals a plus 40 and 2a plus 2b equals 160. solve for a and b?
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60
6b plus 6 equals 2b plus 12 what is b?
1.5
How do you solve for the variable b in 2a plus 2b equals c?
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
5b-4 equals 2b plus 17?
b=7
What is the formula to solve for b a equals 2b plus c?
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
B plus B equals?
=2b
Which of these formulas is rewritten form the original formula to solve for b a equals 2b plus c?
b= 1/2 (a - c)
A plus b plus c equals 2s then 2s-2b is equal to?
2s-2b= a+b+c-2b simplified that would be a+c-b.
How do you solve b plus b plus 18 equals 4b?
I ask my 11 year old son. 2b + 18 = 4b Subtract 2b form each side: 18 = 2b Divide each side by 2: 9 = b which is the same as b = 9, but you knew that, didn't you?
Solve 21 equals 13 minus 2b?
This is the same as: 13-2b = 21 -2b = 21-13 -2b = 8 b = -4
If b equals a plus 40 and 2a plus 2b equals 160. solve for a and b?
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60
6b plus 6 equals 2b plus 12 what is b?
1.5
How do you solve for the variable b in 2a plus 2b equals c?
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
5b-4 equals 2b plus 17?
b=7
Solve for x and y. ax plus by equals a-b bx-ay equals a plus b plus b?
Your two equations are: AX + BY = A - B BX - AY = A + B + B Because you have four variables (A, B, X, Y), you cannot solve for numerical values for X and Y. There are a total of four answers to this question, solving each equation for X and Y independently. First equation: X = (A - B - BY)/A Y= (A - B - AX)/B Second equation: X = (A +2B +AY)/B Y = (BX - A - 2B)/A
If 8b plus 11-3b equals 2b plus 2 what is b?
8b + 11 - 3b = 2b + 2 5b + 11 = 2b + 2 5b - 2b = 2 - 11 3b = -9 b = -3
