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Q: Express 80 as a product of its prime numbers?

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2x2x2x2x5

141

The product of 83 and 89 is 7387

The prime numbers (factors) of 80 are: 2 and 5

As a product of its prime factors in exponents: 24*5 = 80

73

80 = 2 x 2 x 2 x 2 x 5

The prime factorization of 80 is 2x2x2x2x5 (or 24x5).

Prime numbers between 71 to 80 = 73 and 79 Therefore there are 2 prime numbers between 71 to 80.

The prime factors of 80 are 2,2,2,2,5.The product is 2x2x2x2x5, which is 80.

prime numbers between 50 and 80 = 53,59,61,67 ,71,73,79

Two of the factors of 80 are prime numbers: 2 and 5.

Two numbers have a product of 80 their sum is 24?

2 x 2 x 2 x 2 x 5 = 80

There are 3 prime numbers from 80 to 100:83, 89 and 97

The prime numbers between 80 and 100 are 83, 89, and 97.

The numbers 83, 89 and 97 are prime.

73

2 x 37 = 74 As the product is an even number one of the prime numbers must be 2. Then just check all the even numbers between 70 and 80 that is double a prime number: 74 = 2 x 37.

61, 67,71, 73, and 79 are the prime numbers between 60 and 80.

The only number that equals 80 is 80, and it's not a prime number.

Both are not prime numbers, but they are relatively prime.

71, 73, and 79 are three prime numbers between 70 and 80.

Prime numbers between 80 and a 100 are: 83, 89 and 97

number of prime numbers in 71 to 80 = 3prime numbers in 71 to 80 = 71, 73, & 79

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