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# How do you differentiate 2tanx?

Wiki User

2012-01-09 16:08:46

For a number in form af(x) while differentiating with dont interfere with the constant a.

So, it is a d(f(x))/dx

Here assuming were differentiating with respect to x,

we have 2*d(tan x)/dx

From here you have options weather you can differentiate ie based on uv or u/v method. I'll be using u/v (easy to apply for division),

Here's the general form,

(u/v)' = {vu' - uv'}/v^2

d(tan x)/dx =d(sinx/cosx )/dx = {cosx(sinx)' - sinx(cosx)'}/(cos^2)

= {(cos^2 x) - (-sin^2x)}/cos^2 = {(cos^2 x) +(sin^2x)}/cos^2

Since sin^2 x + cos^2 x =1 ,

we have

d(tan x)/dx = 1/cos^2x = sec ^2 x.

Therefore the final answer for,

2d(tan x)/dx = 2sec^2 x

allysia

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2021-06-08 02:59:15
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Wiki User

2012-01-09 16:08:46

Coefficients can be removed when differentiating, i.e. d/dx 2tanx = 2 d/dx tanx

You should know that d/dx tanx = sec2x (either by differentiating sinx/cosx or by just remembering the derivatives of common trig functions, as it will come in handy).

So the answer is 2sec2x

dream gaming

Lvl 2
2021-01-15 07:29:56

2000 points

dream gaming

Lvl 1
2021-01-15 07:30:10
plz give

Deangelo Stoutmire

Lvl 3
2021-11-15 22:21:25

dat

Anonymous

Lvl 1
2020-07-31 03:09:32

Ur answers are too hard