That is not possible. You would have to know one more thing, such as the
rate of acceleration or the distance.
Take a step back and think for a moment about what you're asking.
I'll make up an example that illustrates the situation you've described:
I left my house driving north at 20 miles per hour, and arrived at my office
driving east at 40 miles per hour. How long did the trip from my home to
my office take me ?
Can you see now why it's not possible ?
There is not enough information to calculate the time.
There is not enough information to calculate the time.
There is not enough information to calculate the time.
There is not enough information to calculate the time.
That's truly a tough one. Particularly if you've been skipping the homework, or not
paying attention in class.
Final velocity = (Initial velocity) + (acceleration) x (time).Surely, you can massage this around to solve it for 'time'.The fact that you are given an initial velocity and not just velocity suggests that the motion is accelerated. In that case there is not sufficient information to calculate the time.
There is not enough information to calculate the time.
time = distance divided by speed.
since time is given you are done
More information is needed.
You can only know the distance for sure if acceleration or deceleration is constant. Add the start and end velocities and divide by two and then multiply by the time to get your distance.
The product of velocity and time yields distance travelled if the velocity is constant for the time in question. If velocity is not constant, one must first calculate the average velocity over a given time period before multiplying it by the time involved.
given distance- 200km time-5 hours speed- distance/time 200/5 40km/hr Divide distance by time for speed Divide speed by distance for time Multiply speed and time for distance Those are three ways to make sure you have it right Average Velocity = (change in position) / (elapsed time) Instantaneous Velocity = [limit as elapsed time approaches 0] (change in position) / (elapsed time) Velocity is measured in m/s+ direction
Velocity is in distance/time, so multiplied by 1/distance would give you 1/time. Hope this helps!
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration
You cannot.
This is difficult. We are not told what it is we are to calculate. We are not told how the velocity is changing (which it does, implied by the word "initial"). Suggest re-writing the question.
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
There is not enough information to calculate the answer.
yes...
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
v = 2s/t - u where u=initial velocity, v=final velocity, s = distance and t = time
More information is needed.
If you are only given total distance and total time you cannot. If you are given distance as a function of time, then the first derivative of distance with respect to time, ds/dt, gives the velocity. Evaluate this function at t = 0 for initial velocity. The second derivative, d2s/dt2 gives the acceleration as a function of time.
One example... X = 1/2 A t2 + V0 t + X0 Where X is distance, A is acceleration, t is time, V0 is initial velocity, and X0 is initial distance. This allows you to calculate where you would be given a starting position, velocity, and acceleration, after a specified time, such as in an automobile.
You can't. You need either the final velocity or the acceleration of the object as well, and then you can substitute the known values into a kinematics equation to get the initial velocity.