There is a relationship between power P, voltage V and current I. This relationship is best summarised by this formula: P=IV this gives us (current) I = P/V this gives total current =1200/120 =10 ampere
Power[Watt] = Voltage[Volts] x Current[Amperes], i.e. P = VI -----[1] In current situation: Power = 100 Watt Voltage = 120 Volts Thus, Current I = P/V, from eqn.[1] => I = 100/120 => I = 0.833333333 Amperes . [Answer]
Zero amps will flow. If the outlet is a normal household receptacle outlet in North America, the breaker will trip. This is because the circuit is protected at 15 amps. Using the equation Amps = Watts/Volts = 2400/120 = 20 amps. As you can see this is why the breaker will trip. Using the equation Watts = Amps x Volts = 15 x 120 = 1800 Watts. This is why the maximum wattage allowed by the electrical code on a normal household circuit is 1800 watts.
Just quickly looking at this (it's been a while) but, P = I*V, and Mr. Ohm states... I = V/R substitue V/R for I and you'd get P = V^2/R or... 1.2KW?
120V / 12 ohms = 10amps. 120V * 10amps = 1200 Watts.
For a simple load (e.g., pure resistive like the heater element in an electric oven)
Watts=Amps*Volts
2400 W = 20 A * 120 V
The formula you are looking for is W = E squared/R.
100 watts / 120 volts = .833 amps
20 amps. Watts/volts=amps
Someting
120 power flows through a circuit with 1 amp and 120 volts.
Find out your supply voltage, and divide 65 by it: I(amps) = P(watts)/V(volts) = 65/V
Power (watts) = current (amperes) * voltage (volts) Current (amperes) = voltage (volts)/resistance (ohms) 120 watts = current * 120 volts current = 1 ampere 1 ampere = 120 volts/resistance resistance = 120 ohms
The current is half an amp because amps times volts equals watts.
Forward biase the given diode by using a Variable resistor in the circuit. By adjusting the value of variable resistor you will adjust the voltage being applied to junction diode. First adjust the resistance such that no(negligble) current flows through the circuit. Now start decreasing the value of resistance. Note the voltage across resistor(Vr) when current just starts flowing through the circuit. Then Potential barrier of diode will be: Vb=V-Vr Vb:Barrier Potential V:Battery Voltage Vr:Voltage Drop across resistance when current just starts flowing through the circuit.
4 amps
Ohm's Law Volts = Current x Resistance Amps = V / R 110 / 20 = 5.5 Amps
Ohm's Law Voltage = Current x Resistance Answer is 15/300
Assuming that you mean connected to 120 Volts (V) supply, start with Power(P)=Current(I) x Voltage(V), and if P=V*I, then I=P/V. I=12W/120V=0.1A or 100mA and that is your current.
That depends on the voltage which the current flows through. I = P / U I = 1500 / U Where I is the current in Amperes and U is the effective voltage in Volts. (P is the power)
Ohms are the unit of resistance you find in Ohms LAw which says Volts = Amps x Ohms. You can get a voltage drop across a resistance, but would have to know what current is being used and you would have a potentiometer in effect. You are not "converting 12V" to 10V, your are essentially loosing two volts through a resistor.
Let R be the resistance, V the voltage, and I the current R = V / I R = 120 / 24 R = 5 ohm
600 VDC.
The three electrical quantities are current voltage and resistance. Current is measured in amperes (A) and is the rate at which electricity flows through a conductor. Voltage is measured in volts (V) and is the electrical force pushing the current through the conductor. Resistance is measured in ohms () and is the opposition to the flow of current. Current - measured in amperes (A) Voltage - measured in volts (V) Resistance - measured in ohms ()
120 power flows through a circuit with 1 amp and 120 volts.
-10
V = (I) x (R) = 2 x 12 = 24 volts