Seven, to start with, but the last of these digits is a zero. So effectively there will be six.
5
If the two decimal numbers have x and y digits after the decimal points, then the product has (x + y) digits after the decimal point.
One way is to multiply the numbers ignoring the decimal point. If the first multiplicand has d1 digits after the decimal point, and the second has d2 digits after the decimal point, then their product has (d1 + d2) digits after the decimal point.An alternative for the second stage is to estimate the answer to determine where the decimal point should go.
-- Ignore the decimal point; just multiply the two whole numbers. -- After the multiplication is done, put the decimal point back into the product. Put it in the right place so that the product has as many digits after the point as the original decimal had. If there aren't enough digits in the product to do that, add some zeros to the left end of it.
Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude.
You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.
If the two decimal numbers have x and y digits after the decimal points, then the product has (x + y) digits after the decimal point.
If two decimal numbers have x and y digits after the decimal point respectively, then their product has (x + y) digits after the decimal point.
One way is to multiply the numbers ignoring the decimal point. If the first multiplicand has d1 digits after the decimal point, and the second has d2 digits after the decimal point, then their product has (d1 + d2) digits after the decimal point.An alternative for the second stage is to estimate the answer to determine where the decimal point should go.
-- Ignore the decimal point; just multiply the two whole numbers. -- After the multiplication is done, put the decimal point back into the product. Put it in the right place so that the product has as many digits after the point as the original decimal had. If there aren't enough digits in the product to do that, add some zeros to the left end of it.
2 digits because 1.88*71 = 133.48
Consider the numbers A and B where A has m digits after the decimal point and B has n digits.Then find the multiple A'*B' where A' is A without its decimal point, and B' is B without its decimal point.In that answer insert the decimal point so that there are (m+n) digits after the decimal point.
Ignore the decimal points and multiply the numbers to give the product: 308*29 = 8932Count the number of digits AFTER the decimal points in the two numbers. Two in the first and one in the second, making three in all.That is the number of digits after the decimal point that you want in the answer. So insert the decimal point that many digits from the end of the product.Thus 8932 becomes 8.932Done!
Because the number of digits after the decimal place in a product does not require that.
If the two multiplicands have X and Y digits after the decimal place then their product (before removing any trailing 0s) has (X+Y) digits after the decimal point.
Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude. Digits after (to the right of) the decimal point contribute to the accuracy of the number, not its magnitude (or size). So only the digits to the left of the decimal point contribute to the magnitude.
If two numbers, P and Q, have x and y digits after the decimal point respectively, then P*Q has (x+y) digits after the decimal point.
You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.You must add 9 digits (or 12 digits, depending on the country) after the decimal point, and eliminate the decimal point. Thus (assuming the "short scale") you get: 53,620,000,000.