There are 9 integers.
99 of them.
There are 21 prime numbers between 100-200.
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
50
300
12. 13, if you count 200
"Consecutive" integers are integers that have no other integer between them.
There are 21 prime numbers between 100-200.
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
There are 22 such numbers.
For example, for all numbers between 101-200: for (int i = 101; i
99 of them. Each and every one of the numbers between 100 and 200 is a multiple of itself and 1.
50
Six.
4
10 - 101,111,121, ...
10
There are 100 even numbers between 1 and 200 (inclusive).