20 of them.
20
19
20
20
six 37 39 41 43 45 47
there is 6 and they are 37 39 41 43 45 47
All primes other than two are odd, and two odd numbers add to an even number. So the only possibility is two and 43 minus two. So 2 and 41 is the only pair.
First, the only candidates are odd, so 41, 43, 45, 47, 49 45 is divisible by 5, and 49 by 7, leaving 41, 43, and 47 Now, you can try to divide these number by all of the odd numbers between 3 and themselves (as a simple algorithm), but you will not find that they are divisible by any number other than one and themselves. So, 41, 43, and 47 are prime.
Yes.
31, 33, 35, 37, 39, 41, 43 & 45 = eight odd numbers !
six 37 39 41 43 45 47
37, 39 and 41
there is 6 and they are 37 39 41 43 45 47
43 is an odd number and it is also a prime number
31 37 41 43 47
31 37 41 43 47
31, 37, 41, 43, 47.
They are: 31 37 41 43 and 47
odd numbers between 25 and 45 inclusive are 25 27 29 31 33 35 37 39 41 43 45
There are several combinations of odd numbers that add up to 43. For example, 3 + 29 + 11 is equal to 43, so is 5 + 27 + 11, and many more. In fact, if you allow negative numbers, you have an infinite number of combinations.
They are: 31 37 41 43 and 47