Q + N = 36;.25Q + .05N = 5.20;.25(36-N) +.05N = 5.20;9- .20N = 5.20;3.8 = .20N;N = 19 and Q = 17
17 quarters, 19 nickels
There are 17 quarters and 19 nickels.
The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?
8 quarters and 12 nickels
Two quarters Three nickels Three pennies
2 quarters, 4 dimes, 2 nickels
10 Nickels 2 Quarters = $1.00 4 Dimes 7 Nickels 1 Quarter = $1.00 8 Dimes 4 Nickels = $1.00
The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?
8 quarters and 12 nickels
Two quarters Three nickels Three pennies
There are 11 ways to get $4.10 using only quarters and nickels. These combinations are: 41 quarters 8 quarters, 6 nickels 15 quarters, 2 nickels 3 quarters, 12 nickels 20 quarters, 1 nickel 35 quarters 8 quarters, 5 nickels 15 quarters, 1 nickel 5 quarters, 10 nickels 30 quarters, 1 nickel 1 quarter, 20 nickels
2 quarters, 4 dimes, 2 nickels
10 Nickels 2 Quarters = $1.00 4 Dimes 7 Nickels 1 Quarter = $1.00 8 Dimes 4 Nickels = $1.00
2 quarters, 2 nickels, 3 pennies
Two quarters and a dime. Two quarters and two nickels.
4 quarters 1 nickel 3 quarters 6 nickels 2 quartes 11 nickels 1 quarter 16 nickels 21 nickels So five ways
5 quarters 4 quarters 2 dimes and a nickel 10 dimes and 5 nickels
You need to define variables for the different types of coins, write the corresponding equations, then solve them. One equation for each fact. Here are the equations:5N + 10D + 25Q = 1250 D = 2N Q = 2D
Three: one using only nickels, one using only dimes and one using only quarters!