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If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.

If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.

If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.

If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.

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Q: If the side of a square is doubled in size to 8 by what percent did its area increase?

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If the linear dimensions of a square or a rectangle are doubled, the area of the object will be quadrupled.

No, it will be quadrupled.

if length is doubled then resistivity increases&when area is doubled resistivity decreases.

The area increases, but there's no way to say by how much in general. The percent increase is different in different cases.

the new area will be fourfold, not doubled. try it on squared paper and see how the shape increases from one square into four...

The area increase by four times.

30%

By 44%. Here is how you calculate it: 20% increase is equivalent to an increase by a factor of 1.2 (100% + 20%, converted to decimal). Square that, and you get 1.44 (44% more than the original).

The area would become four times larger. The area increase is always the perimeter increase, squared. For example. If the sides of a square were quadrupled, the area would become sixteen times larger.

Yes it does. By a factor of 4.

The area should increase.

That would depend on the original side lengths of the square which have not been given.

56.25% let side of square is 'a' its perimeter is 4a its area is axa perimeter increase by 25% new perimeter is 5a new sideof square becomes=5a/4= 1.25a its new area is 1.25ax1.25a increase in area in percentage is ((1.25ax1.25a)-(axa))/(axa) *100 =56.25%

Doubling the length of the sides of a square results in the area being quadrupled (four times the original area).

It will increase to four times as much.

The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4

four times the initial value

If the circumference of a circle is doubled, the area will be four times bigger. It's like having a square with one metre sides. If we double the length of sides, that is - two metre long sides. the length around will be eight instead if four metres. The area will not be doubled from one square metre to two square meters. It will be four square metres instead. Lengths only grow in one direction so doubling is doubling, but areas grow in two directions - length and width at the same time. Therefore, areas grow and grow, doubling this way and doubling that way, so the doubling is doubled making it four times. Trebling would be trebled making a three times length increase into a nine times area increase.

For trapezoids the area increases by factor of 4 if the dimensions are doubled. Using the square to explain why this ratio works, consider two squares, one 1x1 and the other 2x2, the area of the first is 1 sq. unit, the second 4 sq. units.This is because area goes up by the square of the sector of the increase. For double sized dimension the increase is 4 times, for triple sized dimensions it is 9 times

If you double the dimensions, then the perimeter is doubled. However, the area is quadrupled. For example, let's say that a side of a square is x units. The perimeter would be 4x, and the area x2. Now, let's double the dimension into 2x. Now, the perimeter is 8x, and the area is 4x2. As you can see, the perimeter is doubled and the area is quadrupled.

10

200%. Careful here! An 800% increase is equivalent to multiplying by 9 - NOT 8. So the sides need to be multiplied by sqrt(9) = 3. That is an increase of 200%

The area is multiplied by 4, not doubled.

Area is quadrupled (*4) and perimeter is doubled.

It is a 22% increase

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