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then 3 in next row 2 in the next and 1 in front
Edit: assuming you are referring to the 10-pin bowling, there are four in the back row, not five, as was previously answered by someone else.
Considering the 5 + 3 + 2 + 1 = 11, it is fairly clear that the pins are not set up in that war.
In tenpin bowling, there are ten pins per lane. In 9 pin there are nine. In 5 pin there are five.
The (7 - 8 - 9 - 10) are in the back row. That's 4 of the 10. The fraction is 4/10 = 0.4
Assuming 10-pin bowling, there are 4 pins in the back row, so 4/10ths (40%) of the pins are in the back row.