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Q: What 7 numbers has a range of 10 and a mean of 12?

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12 and 8

(10, 12, 12, 13, 13)

Mean: 20.2222222 Median: 12 Mode: 11 Range: 79

four and sixteen16 - 4 = 1216 + 4 = 20 then 20 / 2 = 10Half of 12 is 6, therefore the two numbers 10 - 6 = 4 and 10 + 6 = 16 will have a mean of 10 and a range of 12.Further numbers can be added between 4 and 16 as long as their mean is still 10, eg the data sets:{4, 16}{4, 10, 16}{4, 8, 12, 16}{4, 8, 10, 12, 16}{4, 7, 9, 14, 16}all have a mean of 10 and a range of 12. There is an infinity of such sets.

There is no single answer to that. You could come up with many sets of numbers that would have those properties.

eight and twelveas mean is 10 then startwith 10 then divide the range of 4 by 2 = 2and take 2 off and add 2 on10 - 2 = 8 and 10 + 2 = 12Check:8 + 12 = 20 then divide those 2 numbers by that 2 so 20 / 2 = 10 mean12 - 8 = 4 range

the range is 10

Range = Maximum - Minimum = 20 - 8 = 12.

Mean: 11.6 Median: 12 Mode: 10, 12, 15, 16, 5 Range: 11

One possible set is {9, 9, 10, 11, 12, 15, 18}

8, 9, 11 and 12

16 and 8 is the simplest example. Mean = (16 + 8) / 2 = 12 Range = 16 - 8 = 8

8 and 12 have a mean of 10 and a range of 4

Range: 34 Mean: 21.71 Median: 15 Mode: 10

As there are two numbers, the range is the difference between themAs there are 2 numbers the mean is exactly in the middle of them.Thus half the range is less than the mean and half the range is greater than the mean.Thus the two numbers are 10 ± (4/2) = 10 ± 2 = 8 and 12.Algebraically, this can be seen:Let the two numbers be x and y with y > xThen:their range is y - x = 4; andtheir mean is (x + y) / 2 = 10{2} can be rearrange to give x + y = 10 × 2 → y + x = 20adding {3} to {1} yields: (y + y) + (-x + x) = 20 + 4 → 2y = 24 → y = 12subtracting {1} from {3} yields (y - y) + (x - -x) = 20 - 4 → 2x = 16 → x = 8→ the two numbers are 8 and 12.

(10, 12, 12, 13, 13)

The mean is the average of the numbers Add up all the numbers, then divide by how many numbers there are. Example What is the mean of these numbers? 6, 20, 10 1. Add the numbers 6 + 20+ 10 = 36 2. Then divide by how many numbers ( 3 numbers) ( 6 20 10 ) 3. 36 divide by 3 = 12 The mean is 12

To find the range of a set of numbers, subtract the lowest value from the highest; so the range is 12 - 4, or 8.

There are an infinite number of possibilities. One set is 8, 12, 12, 12 and 16

Because the mode is 5, we know at least two of the numbers are 5. Because the median is 12 and we have five numbers, we know one of them is 12. Because the range is 10 and the smallest number we know so far is 5, we'll try 15 for a fourth number. This gives us: 5, 5, 12, 15 The mean is 10, so we know the sum of all five numbers is 50. The sum of the four numbers we have so far is 5+5+12+15 = 37. Thus, the fifth number is 50-37 = 13. That gives us 5, 5, 12, 13, 15. These five numbers fit all the criteria.

mean: 9 ordered sample: 7, 8, 8, 10, 12 median: 8 mode: 8 range: 12 - 7 = 5

You can represent 2^12 or 4096 numbers in 12 bits, if that's what you mean?

28,17,45,32,29,28,14,27

The mean average of the given numbers is 10

what i have is mean is 22.2,median which is the middle is 23,range is 26, and mode is 12

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