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Equation of circle: x^2 +y^2 -6x +4y +5 = 0

Completing the squares: (x-3)^2 +(y+2)^2 = 8

Radius of circle: square root of 8

Center of circle: (3, -2)

Circle makes contact with the x axis at: (1, 0) and (5, 0)

Slope of 1st tangent: 1

Slope of 2nd tangent: -1

1st tangent line equation: y = 1(x-1) => y = x-1

2nd tangent line equation: y = -1(x-5) => y = -x+5

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6y ago

They are: x - y - 1 = 0 and x + y - 5 = 0

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Q: What are the tangent line equations of the circle x2 plus y2 -6x plus 4y plus 5 equals 0 when the circle passes through the x axis?
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