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Q: What is 2a times b?

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2A plus 3B times 2A - 3B = 4A2 - 9B2; this is an example of the general formula (a + b)(a - b) = a2 - b2.

a-^2a-b^-a-b

2a*4b*(-3c) = ? 2 * 4 * -3 * a * b * c = ? -24abc

2a+b=2a+b. Without a value for a and b, the expression has no value.

A=-4 b=5 2a=-8 2b=10 5ab=-100 2a x 2b x 5ab= -8000

A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b

Subtract 2a from each side: P - 2a = b ie b = P - 2a

4a² - b² = (2a + b)(2a - b)

2a-3+4b-2a-b-2a-b-3+5 Can be simplified to: 3b-1

(2a - b)(2a + b)

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It is 2a-b simplified

2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------

No. 2a is one thing, 3b is another. If you add them together, they become 2a + 3b. 5ab indicates that multiplication has taken place. 5 times a times b = 5ab

2a-3+4b-2a-b-3+5=3b-1

-b/2a. i think.To show this, consider this equation:y = ax² + bx + cFactor out the a:y = a(x² + bx/a + c/a)Then, complete the squares to get:y = a(x² + bx/a + (b/(2a))² + c/a - (b/(2a))²)= a((x + (b/2a))² + c/a - (b/(2a))²)= a(x + (b/2a))² + c - b/(4a)By the vertex form:y = a(x - h)² + k where x = h is the axis of symmetry.So the general axis of symmetry for the quadratic equation is x = -b/(2a).

x=-b/2a [negative B over 2A]

4(4a2 - b2) 4(2a + b)(2a - b)

3+2*A+B*4/2-4 = 3 + 2A + 2B - 4 = 2A + 2B - 1

a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)

2a+2b+3a+3b+a+b= 6a+6b 2a+3a+a=6a 2b+3b+b=6b

2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60

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2a + 3b = 13 a + b =7, 2a + 2b = 14 (2a + 3b) - (2a+2b) = b 13 - 14 = -1, so b = -1 a+(-1) = 7, a = 8 Check: 2(8) + 3(-1) = 16-3 =13 (8) + (-1) = 7

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