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Find the difference (-2ab-2a-5)-(6ab plus 2)?
4ab - 2a - 7
What is 4ab x 3a?
4ab * 3a = 12a2b -----------
Suppose x and y are odd prove xy is odd?
Write x and y in terms of integers, which we call a and b. For some integer, x = 2a + 1 y = 2b + 1 Multiplying them, you get: xy = (2a+1)(2b+1) = 4ab + 2a + 2b + 1 Since the first terms are even, adding one makes the final result odd.
Er equals 2a plus b inches what is the area of square oser?
4a2+4ab+b2 in2
2a x 2a?
The answer is 4a^2.
2a x 2b?
Urmm 4ab ?
Simplify 5a³ - 4ab plus 2a³ as much as possible?
5a³ - 4ab + 2a³ = (5+2)a³ - 4ab = 7a³ - 4ab.
How do you factorise 4ab?
2a(2b) Would Give You The Answer 4ab. 2x2 = 4 And a x b = ab.
What is the answer to 2ax2b?
2a*2b = 4ab
How do you simplify an expression in the format of 4a2 plus 4ab - y2 plus b2?
4a2 + 4ab - y2 + b2 You cannot simplify this expression because it does not contain like terms, but you can factor it such as: 4a2 + 4ab - y2 + b2 = (4a2 + 4ab + b2) - y2 = (2a + b)2 - y2 = [(2a + b) - y][(2a + b) + y]
Find the difference (-2ab-2a-5)-(6ab plus 2)?
4ab - 2a - 7
How do you factorise 4ab-2ac?
2a(2b-c) :P
What is 4ab x 3a?
4ab * 3a = 12a2b -----------
Which is a factor of 6a2 plus 5ab - 6b2?
Considering the minus sign between 5ab and 6b2 then we have the polynomial as 6a2 + 5ab - 6b2. The polynomial is a quadratic polynomial.Steps to factorize a quadratic polynomial:1 - Multiply first term by third term. 6a2 x (-6b2) = -36a2b22 - If possible break the second term into two terms such that they multiple to -36a2b2. If not then it is factorized by Sridharacharya's formula.5ab can be broken as 9ab + (-4ab).These two terms multiply to give -36a2b2.So we can write 6a2 + 5ab - 6b2 = 6a2 + 9ab + (-4ab) - 6b2.6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)(3a - 2b).So the factors are (2a + 3b) and (3a - 2b).
How do you factorise 4ab plus 2ac?
5 = 1 x 5, 21 = 3 x 7 3 x 5 = 15, 1 x 7 = 7, 15 - 7 = 8 so: (5x + 7)(x - 3)
Suppose x and y are odd prove xy is odd?
Write x and y in terms of integers, which we call a and b. For some integer, x = 2a + 1 y = 2b + 1 Multiplying them, you get: xy = (2a+1)(2b+1) = 4ab + 2a + 2b + 1 Since the first terms are even, adding one makes the final result odd.
Find the area of a rectangle that has a base of 4a cm and a height of 2a plus b cm?
You have to multiply base x height - in this case, you obtain (4a)(2a+b). This can't be simplified; you can leave it as it is (factored), or multiply it out to obtain 8a2 + 4ab.
