5a
5a2
5a times 5a would equal 25a^2.
5a or 4a squared
15ab
10ab
5a times 3a minus 8a = (5*3)*a2 - 8a = 15a2 - 8a
2a + 3a = 5a
5a plus 2b
The GCF is 5a.
Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.
-8/7a
5A-2
5a = a + a + a + a + a