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Q: What is b plus 14?

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There is no such word as "abrical".The algebraic expression for b plus 14 is b + 14

It is: b = -3

b + 14. There is nothing further than can be done without additional information about b.

1-6b+7=14 8-6b =14 -6b =6 -b =1 b =-1

14*13=182

b = 14

A=8 B=4 C=14 Yes, I know I'm a genius. Mak - the all knowing one. MWAHAHAH!

y = x2 + 14x + 21 a = 1, b = 14 x = -b/2a = -14/2*1 = -7

14*12=168168+41=209

12

84

14 x 7 = 28 + 70 = 98

4b.

b2+11b-42 = (b+14)(b-3) when factored

y = x2 + 14x + 21; a = 1, b = 14, c = 21 x-coordinate = -b/2a = -14/2 = -7 if it is y = x2 + 14 + 21, the x-coordinate is zero, since b = 0.

4b

4b

a+b = 17a+c = 36 ----> c = 36 - ab+c = 25 ----> c = 25 - bSo since both are c, we say36 - a = 25 -bFrom this : 11 = a - bLook at 1st eqn: a + b = 17Now we have: a - b = 11 ----> a = 11 + bSo we can substitute that into a + b = 17 to make:(11 + b) + b = 1711 + 2b = 17So b = 3If b = 3, then a + 3 = 17 , so a = 14, 3 + c = 25, so c = 22So a=14, b=3, c=22, so a+b+c = 14+3+22 = 39

b+b+b+c+c+c+c =3b+4c

134

a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19

3b

b + b + b + c + c + c + c = 3b + 4c

a-b+a-b+2b+a = 4a

b + a + b - a = 2b

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