5/p - 10.
4p - 9 > 15
Expressed algebraically, this is equal to 22p - 8.
p is less than or equal to 4
It is: p-2
p(a) = 1/3, p(b) = 1/2, p(a and b) = p(a)*p(b) = 1/6
p is less than 12.
Comparative operators are used to compare the logical value of one object with another and thus establish the rank (ordering) of those objects. There are six comparative operators in total: p<q : evaluates true when p is less than q p>q : evaluates true when p is greater than q p<=q : evaluates true when p is less than or equal to q p>=q : evaluates true when p is greater than or equal to q p!=q : evaluates true when p is not equal to q p==q : evaluates true when p is equal to q
Less than 75 cents.
It is greater.
Assuming the question refers to P less than 5, the answer is P can have any value that is less than five within the domain of P.For example, if P is an integer, P can be 4 or -1 but it cannot be 1.3If P is rational, it can also be 1.3 but it cannot be sqrt(1.3).
It is an inequality than can be solved for p: 5 ≥ p - 3 → p - 3 ≤ 5 → p ≤ 8 So any value less than, or equal to, 8 will do for p.
If the signs of the numerator and denominator are different then the fraction is less than 0 and, therefore, obviously less than one half.If the signs are the same then if the absolute value of the numerator is less than or equal to half the absolute value of the denominator, then the fraction is less than or equal to one half.Algebraically,p/q
yes, p orbital can have only 6 electrons but not more than that
Let's call the prime p, the multiple 7n, and the counting number c. So: p = c3 - 7n, p > 1, 0 < c < 10, n > 0 c can't be 1 or 2, since p and n have to be positive. c = 3, then p = 27 - 7n n = 2, then p = 13 So, the smallest prime that meets the conditions is 13.
The concept of the number of factors is appropriate only with positive integers. Otherwise, if p is a factor of the given number n, do you also count -p? That would double the number of factors. So are there 3 factors or 6?