- Planck's constant ^.^
hydrogen
A letter such as h in an equation is the unknown variable.
The energy associated with photons in an electromagnetic waves increases as the wavelength decreases. The equation is E = hc/λ, where E is energy of a photon, h is Planck's constant (6.62606957×10-34 J.s), c is the speed of light in a vacuum (299,792,458 m/s) and λ is wavelength.
No, they don't have de-broglie wavelength since this concept is valid for substances having some mass. This concept is mainly used to calculate the wavelength of electrons. The photons are just energy packets and they are not matter and don't have weight. Therefore, they don't have de-broglie wavelength
The size of the wavelength w determines the energy of the wave. E = hc/w =cp and the Momentum of the wave, p=h/w.
You can use the formula: E = hc / lambda Where: "h" is Planck's constant; "c" is the speed of light; "lambda" is the wavelength.
We need to know the equation E=h where h=plancks constant . From this equation you can see that energy and frequency are directly related ( one increases as the other one dicrease )
- Planck's constant ^.^
I assume the equation you're looking for is E=hv or E=hc/lambda. h is plancks constant and c is speed of light in m/s. lambda is in metres
Light has matter E= mc2 = hc/r thus m=h/cr.
Use hc/lambda = E [energy] So lambda = hc / E Use h = 6.626 x 10^-34 and c = 3 x 10^8 Ofcourse E is given in joule You could solve by yourself
Planck's idea that electromagnetic energy has proportional to its frequency , E = hf and the constant of proportionality is called Planck 's Constant h. Planck conceived of the energy as a particle like energy called a Photon. Planck's Energy should be called Photon Potential Energy E = hc/r
the simplest way is to use a spectrometer more specifically emission spectrum in with a machine refracts the light radiation into colors which you can use to match up wavelength another way is using planks law if you have the energy levels of the atom source for example/ E=hc/lambda where lambda is the wavelength, E is the energy, h is the planks constant and c is equal to the speed of light. we can rearrange this equation to give lambda=hc/E so for example a hydrogen emits radiation at E= to 3.01x10-19J we use the rearranged equation to give (6.63x10-34)(3.00x10 8) / (3.01x10-19) = 6.63 x10-7 or 663nm
It is called dissolving the acid. balanced equation: HCl+H(OH)-> H+Cl+H(OH)
The energy associated with photons in an electromagnetic waves increases as the wavelength decreases. The equation is E = hc/λ, where E is energy of a photon, h is Planck's constant (6.62606957×10-34 J.s), c is the speed of light in a vacuum (299,792,458 m/s) and λ is wavelength.
E = mc2 j = 4out h = 9in
the simplest way is to use a spectrometer more specifically emission spectrum in with a machine refracts the light radiation into colors which you can use to match up wavelength another way is using planks law if you have the energy levels of the atom source for example/ E=hc/lambda where lambda is the wavelength, E is the energy, h is the planks constant and c is equal to the speed of light. we can rearrange this equation to give lambda=hc/E so for example a hydrogen emits radiation at E= to 3.01x10-19J we use the rearranged equation to give (6.63x10-34)(3.00x10 8) / (3.01x10-19) = 6.63 x10-7 or 663nm
610 nm (Explanation): Use the formula E=hc/λ for this problem. Plug in E, energy, or 3.26 x 10 ^ (-19) and plug in h, Planck's constant, 6.626 x 10 ^ (-34) and c, speed of light, or 3.0 x 10 ^ 8. To find wavelength, we will change formula into λ=hc/E. So multiply h and c, THEN divide by E to get solution.
C6H3O73- -> C5H4O5 + CO2 + H+ + 4 e-