First we need to find the L.C.M. of 40, 48 and 60.
40 = 2x2x2x5
48 = 2x2x2x2x3
60 = 2x2x3x5
After taking out common factors, we have
L.C.M. = 2x2x2x3x5x2 = 240
To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240.
Remainder = 159
Subtracting this remainder from 9999 we get 9999 - 159 = 9840.
So, the required answer is 9840.
40 = 2x2x2x5
48 = 2x2x2x2x3
60 = 2x2x3x5
After taking out common factors, we have
L.C.M. = 2x2x2x3x5x2 = 240
To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240.
Remainder = 159
Subtracting this remainder from 9999 we get 9999 - 159 = 9840.
So, the required answer is 9840.
99882
How about: 960
99,990.
35 x 285 = 9975 The highest three-digit number divisible by 35 is 9975.
10080
99882
9960
999996
The greatest three digit number that is divisible by 7 is 994.
How about: 960
The greatest 4-digit number that is divisible by 16 is 9984
There is no 4-digit number that is divisible by zero.
The integers divisible by those 5 numbers are exactly the multiples of 1008. The largest multiple of 1008 which is still a four-digit number is 9*1008 = 9072.
The greatest 3-digit number that is not divisible by 2, 3, 5, or 10 is 997.
There is no limit to the number of digits.If, for example, a X is a k-digit number which is divisible by 4 then 10*X is divisible by 4 and 10*X will be a (k+1)-digit number.
99,990.
It is 99992.