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The LCM of 20, 36, and 45 is 180.

We look at the largest number, 45.

For it to be a multiple of 20, it must end with a zero and have an even second-last digit. To get 45 to end with a zero, we can multiply it by 2, which gives us 90.

90 does not have an even second-last digit, so once again we multiply it by another 2, which gives us 180. 180 ends with a 0, and has an even second-last digit.

If you then attempt to divide 180 by 20, 36 and 45, you'll find that it divides perfectly into all 3.

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8y ago

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