Volume of cuboid = 96 cm^3 = 96000 mm^3Length of cuboid = 60mm
Therefore cross-sectional area = 96000/60 = 1600 mm^2
Then either the cuboid is 40 mm x 40 mm with a length of 60 mm or
it is 60 mm x 60 mm square with a length of 1600/60 mm.
It is possible to prove that the largest cylinder is one whose circular face [base] is parallel to the square cross-section.
In the first case the cylinder has a radius 20 mm and height 60 mm => vol = 24000*pi mm^3, or
the cylinder is 30 mm * 30 mm and height 1600/60 mm => vol = 24000*pi mm^3.
The question contains measurements in mm and in cm and so it is not clear what units the "nearest hundredths" refers to. Since I have done the calculations in mm, the answer is
24000*pi = 75398.22 mm^3.
The answer is 452.16.
0.07 is already to the nearest hundredth.
4.89
what is the nearest hundredth to 87.8
To the nearest hundredth it is 0.15
0.33 is at the nearest hundredth.
It is 3.45 to the nearest hundredth
0.21 to the nearest hundredth.
It is 81.10 to the nearest hundredth
13.00 is at the nearest hundredth.
To calculate the surface area of a cylinder, you can use the formula ( SA = 2\pi r(h + r) ), where ( r ) is the radius and ( h ) is the height of the cylinder. If you provide the values for the radius and height, I can calculate the surface area for you. Otherwise, you can substitute the values into the formula to find the answer to the nearest hundredth.
It is already to the nearest hundredth as 9.69