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The simplest rule that will generate the 4 terms, and the nth term is
Un = 2n2 + n + 3
Then Sn = Sum for k = 1 to n of (2k2 + k + 3)
= 2*sum(k2) + sum(k) + sum(3)
= 2*n*(n+1)*(2n+1)/6 + n*(n+1)/2 + 3*n
= (2n3 + 3n2 + n)/3 + (n2 + n)/2 + 3n
= (4n3 + 9n2 + 23n)/6
The simplest rule that will generate the 4 terms, and the nth term is
Un = 2n2 + n + 3
Then Sn = Sum for k = 1 to n of (2k2 + k + 3)
= 2*sum(k2) + sum(k) + sum(3)
= 2*n*(n+1)*(2n+1)/6 + n*(n+1)/2 + 3*n
= (2n3 + 3n2 + n)/3 + (n2 + n)/2 + 3n
= (4n3 + 9n2 + 23n)/6
The simplest rule that will generate the 4 terms, and the nth term is
Un = 2n2 + n + 3
Then Sn = Sum for k = 1 to n of (2k2 + k + 3)
= 2*sum(k2) + sum(k) + sum(3)
= 2*n*(n+1)*(2n+1)/6 + n*(n+1)/2 + 3*n
= (2n3 + 3n2 + n)/3 + (n2 + n)/2 + 3n
= (4n3 + 9n2 + 23n)/6
The simplest rule that will generate the 4 terms, and the nth term is
Un = 2n2 + n + 3
Then Sn = Sum for k = 1 to n of (2k2 + k + 3)
= 2*sum(k2) + sum(k) + sum(3)
= 2*n*(n+1)*(2n+1)/6 + n*(n+1)/2 + 3*n
= (2n3 + 3n2 + n)/3 + (n2 + n)/2 + 3n
= (4n3 + 9n2 + 23n)/6
Wiki User
∙ 10y ago
Wiki User
∙ 10y agoThe simplest rule that will generate the 4 terms, and the nth term is
Un = 2n2 + n + 3
Then Sn = Sum for k = 1 to n of (2k2 + k + 3)
= 2*sum(k2) + sum(k) + sum(3)
= 2*n*(n+1)*(2n+1)/6 + n*(n+1)/2 + 3*n
= (2n3 + 3n2 + n)/3 + (n2 + n)/2 + 3n
= (4n3 + 9n2 + 23n)/6
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nth term = 5 +8n
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The nth term is 3n+7 and so the next number will be 22
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nth term = 5 +8n
What is the formula for the nth term of this sequence -1-7-13-19-25?
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What is the nth term of 10 13 16 19?
The nth term is 3n+7 and so the next number will be 22
What is the Nth term of 4 7 10 13...?
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What is the nth term for the sequences 7 13 19 25?
what will the eight number be. 1, 7, 13, 19, 25, 31 ...
What is the nth term 9 13 17 21?
It is 4n+5 and so the next term will be 25
What is the nth term for 1 7 13 19?
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
What is the nth term for -7 -10 -13 -16?
75988 to the 7th
