Study guides

☆☆

Q: What is the positive square root of 1 trillion?

Write your answer...

Submit

Still have questions?

Related questions

± 1 million

Ordinarily, the square root of -70 does not exist since a positive number squared or a negative number squared results in a positive number. If complex numbers are permitted, then the square root of -70 is i√70 ~= 8.367i where i is the imaginary square root of -1 such that i2 = -1.

The numbers 1 and negative 1 (-1) are both square roots of positive 1.The square root of negative 1 is the "imaginary" number i.

You cannot in real numbers because the square of any number, negative or positive, is positive. However, -25 does have a square root in complex numbers: it is + or - 5i where i is the imaginary square root of -1.

yes, a positive square root is any positive number which is found as an answer when rooting a number.additional. The square root of any positive number will itself be positive.To complete the picture, the square root of a positive number is considered to be either positive or negative; for both answers would give a positive number when squared.The square root of a negative number is slightly more difficult, for that requires to find the square root of -1. Which is considered to be i. So i2 = -1.This concept is of quite important practical value in electrical engineering, but is not met with in ordinary life.

The square root of a negative real number is an imaginary number.We know square root is defined only for positive numbers.For example,1) Find the square root of (-1)It is imaginary. We say that square root of (-1) is i.In fact they are not real numbers.2) Find the square root of (-4)-4 can be written as (-1)(4)Square root of 4 is 2 and square root of (-1) is iSo, the square root of -4 is 2i.Similarly, we can find the square root of other negative numbers also.Source: www.icoachmath.comAn imaginary number is defined to handle square roots of negative numbers. The imaginary unit i is defined as the 'positive' square root of -1.

It is +/- 10i where i is the imaginary number which equals the square root of -1.

The principal root of a number is the positive real square root of the number - if it exists. Since -25 is negative, it does not have a real square root. Its square roots are the imaginary numbers +/-5i where i is the [imaginary] square root of -1. i is neither positive nor negative and so neither +5i nor -5i is a principal root.

The square root of 1 is also 1, so then you just take the square root of that, which is, again, 1.

0

The square root of 1/9 is 1/3 because the square root of 1 is 1 and the square root of 9 is 3.

no, it is actually not a real number. It falls under the category of a imaginary number which is the square root of -1 or as the variable i Because the square root of -4 is 2i because the square root of 4 is 2 and if you take i out it will maek it a positive so it goes like this -4 SR= 2i -9 square root= 3i and so on

Same Square root of 1 is 1

Square root of 1/2 = (1)/(square root of 2) = 1/1.4142 = 0.7071 Also Square root of 1/2 = Square root of 0.5 = 0.7071

The square root of 1 is 1.The square root of 0 is 0.

27i where i is the square root of -1.

y = square root of x y = x(1/2) y' = (1/2)x(1/2 - 1) y' = (1/2)x(-1/2) y' = (1/2)(square root of x)

the square root of 1 is 1. The square root of -1 is j (if you are an engineer) or i (if you are a math geek)

It is: 1+1+8 = 10

a quarter is 1/4 and square root of 1/4 is square root (1/4)=square root of 1 divided by square root of 4 which is 1 divided by 2. So the answer is 1/2

when x is a negative number --- is a wrong answer since square root of a negative number is not defined. So x has to be zero or a positive number. The correct answer is that when x lies between 0 and 1 (with both limits excluded), its square root is greater than the number itself. Of course at both limits, the square root (assuming the positive square root - since a square root of a number can be positive or negative, both with the same absolute value) is the same as the number.

1, as the square root of 1 is 1, and 1 itself is a square of 1.

Treat it like a positive and add an i. Explanation: The square root of negative nine is equal to the square root of nine times negative one is equal to the square root of nine times the square root of negative one. The square root of negative one represented by an italic lower case i. The square root of negative nine is 3i. √-9 = √9 * -1 = √9 * √-1 = 3i

The square root of 1 is just 1

x2+3i=0 so x2=-3i x=square root of (-3i)=square root (-3)square root (i) =i(square root(3)([1/(square root (2)](1+i) and i(square root(3)([-1/(square root (2)](1+i) You can multiply through by i if you want, but I left it since it shows you where the answer came from. Note: The square root of i is 1/square root 2(1+i) and -1/square root of 2 (1+i) to see this, try and square them!