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What is the sum of the product and difference of 8 and 4?
(8*4) + (8-4) = 32 + 4 = 36 ^ ^ sum ^ product and difference
Two real number whose sum is 8 and whose product is maximum?
two real numbers, whose sum is 8 and product is max, are 4,4. 4+4=8 and 4*4=16.
Two numbers have a product of 16 and a quotient of 4 what are they?
8 and 2. 8 x 2 = 16 8/2 = 4
What is the product of -2 and -4 and -7 and -8?
-2 x -4 x -7 x -8 = 448
Which pair of numbers with sum 8 has largest product?
4*4 = 16 (4+4 = 8)3*5 = 15 (3+5 = 8)2*6 = 12 (2+6 = 8)1*7 = 7 (1+7 = 8)0*8 = 0 (0+8 = 8)So 4 and 4 produce the largest product and still have the sum of 8.Assumptions:only integers,that this can be extrapolated (-1*9 < 0*8 etc)
What is the product to 8 and 4?
8 x 4 = 32Note: product is a multiplication.
What is the product for 4 times 8?
The product for 4 times 8 is 32. The product is the answer you get when you multiply numbers together.
What is the sum of the product and difference of 8 and 4?
(8*4) + (8-4) = 32 + 4 = 36 ^ ^ sum ^ product and difference
Divide 12 into two parts such that their product is 32?
addition of 8 & 4 I.e 8+4 = 12 Product of 8 X 4 = 32
What is the product of half the sum of -16 and 8 and twice the sum of -5 and 9?
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
What is the product of the numbers 4 and 8?
1,2,4
The product of 2 and 4?
8
The product of 4 and 8?
32
Add 4 to the product of 8 and 4?
36
What is the product of -8 multiplied by -4?
-4
The product of all the factors of 8 is equal to?
The factors of 8 are 1, 2, 4, and 8. Therefore, the product is 1 x 2 x 4 x 8 = 64.
Two real number whose sum is 8 and whose product is maximum?
two real numbers, whose sum is 8 and product is max, are 4,4. 4+4=8 and 4*4=16.
