When multiplying, the number of significant numbers in the answer should be the same as the fewest significant figures in the problem. Both 13.5 and 3.00 have three significant figures, so the answer will have three significant figures. 13.5 x 3.00 = 40.5 exactly (no need to round).
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
There are 2 significant figures in 7.8x109^?
There are two significant figures which are the 5 and the 4. 0.054 = 5.4 x 10^-2
In both cases, there are 2 significant figures.
Two. When multiplying or dividing the answer is rounded to the fewest significant figures in the given measurements. 0.55 has only two significant figures, so the answer can have only two significant figures.
Count the significant figures in each number. Calculate the minimum of these numbers. Do the multiplication Round the product to the LEAST number of significant figures, determined above.
300 only has one significant digit.
4.884 has four significant figures and 2.25 has three significant figures. 4.884 x 2.25 = 10.989 = 11.0 rounded to three significant figures. When multiplying or dividing, the result must have the same number of significant figures as the number in the problem with the fewest significant figures.
Significant figures are very important when it comes to calculations. If the mass of an electron is 9.10939 x 10-31 then its significant figures are: 9 x 10^-31( correct 1 significant figure), 9.1 x 10^-31 kg ( correct to 2 significant figures), 9.11 x 10^-31 (correct to 3 significant figures), and 9.109 x 10^-31 (correct to 4 significant figures).
It has 5 significant figures - one trailing zero is significant.
To find 45 percent of a number, multiply the number by 0.45. In this instance, 0.45 x 300 = 135. Therefore, 45 percent of 300 is equal to 135.
29.05 to 3 significant figures
6.5211 x 104 = 678.1944 678.1944 has 7 significant figures
There are 2 significant figures in 7.8x109^?
There are two significant figures which are the 5 and the 4. 0.054 = 5.4 x 10^-2
The number 1.84 x 103 has three significant figures, 1.84. The 103 part of the number does not count when determining significant figures.
5 significant figures Each figure that contributes to the accuracy of a value is considered significant. So 2.9979 has 5 significant figures. The 10^8 does not contribute to the accuracy as it simply indicates the number of trailing zeroes (i.e. 299,790,000) that are simply a result of rounding from the actual value (299,792,458)
(4.73*1000*0.568)+1.61 = 2688.25 meaning that it has 6 significant figures