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128 = 64 x 2 so sqrt = 8 x root 2 or "8 root 2"

128 = 2^7 = 2^6 × 2

→ √128 = √(2^6 × 2) = √(2^6) √2 = 2^3 √2 = 8 √2

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8y ago
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Wiki User

14y ago

128 = 27

So sqrt(128) = sqrt(27) = sqrt(26)*sqrt(2) = 23*sqrt(2) or 8*sqrt(2)

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Q: What is the square root of 128 in radical form?
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