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Q: What is the sum of 40 and a difference of 10?

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25 and 15

15 and 25

It's 25 and 15

The numbers are 25 and 15

The numbers are 25 and 15

2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.

Thw two numbers are 25 and 15 because 25+15 = 40 and 25-15 = 10

The two numbers needed are 25 and 15

50

40

int sum = 0; for(int i = 10; i <= 40; i += 2) { sum += i; } printf("Sum of all even numbers between 10 and 40(inclusive) is %d\n", sum);

10 + 4 = 14 10 x 4 = 40 10 - 4 = 6 or 4 - 10 = -6 so your answer is 6 or -6

24 + 16 = 40

The sum is 50 and 31/40 The difference is 1/40

The difference is 5.

The answer to your question is 10 and three.10 + 3 = 13 (Sum)10 - 3 = 7 (Difference)I hope this helps.

75 is LCM The numbers are 15 and 25 15 + 25 = 40 25 - 15 = 10 75 / 15 = 5 75 / 25 = 3

The two numbers are 10 and 2

The sum of two numbers between 20-40 is 58. The difference is 12

Sum of numbers = 40 Count of numbers = 4 Average = Sum/Count = 40/4 = 10

The sum of 75 and 75.

In C: #include <stdio.h> int main(void) { int i, sum=0; for (i=10; i<=40; i+=2) { sum += i; } printf("%d\n", sum); return 0; }

12 and 22

They are 10 and 5