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Q: What is the the exterior angles of a 24 sided polygon?

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The exterior angles of any polygon add up to 360. 360/15 = 24

Exterior angles: 360 degrees Interior angles: 3,960 degrees

Sum of exterior angles = 360 deg Number of exterior angles = 360/24 = 15 So it is a 15-sided polygon

assuming it is a regular polygon: the total exterior angles of any regular polygon add up to 360° therefore 360/15=24°

Interior angles using the formula: (24-2)*180 = 3960 degrees Exterior angles: 360 degrees

24 degrees

Each exterior angle measures 15 degrees

360 degrees is.

((180 x 24) - 360)/24 = 3960/24 = 165o

15 degrees

It is: 360/24 = 15 degrees

Sum of exterior angles = 360 Number of equal angles = 360/15 = 24. So 24 sides.

Each exterior angle measures 24 degrees

15 equal sides

If interior angle is 165 then exterior must be 15.Exterior angles of regular n-sided polygon = 360/n.As 360/n = 15, n must be 24

The interior angles of a regular polygon cannot be less than 60 degrees so 24 degrees is not possible. ------------------------------- However a regular polygon with EXTERIOR angles of 24° has 360° ÷ 24° = 15 sides.

A 24 sided polygon is called a icosikaitetragon.

360/24 = 15 sides

The question cannot be answered except in the case that the polygon is regular. So, even though it does not say so in the question, if we assume that the polygon is regular, then each exterior angle is 360/15 = 24 deg. And since it is supplementary, each interior angle is 180-24 = 156 deg.

The constructed polygon name for a 24-sided regular polygon is an icosikaitetragon.

The sum of the interior angles of a polygon is 2n - 4 right angles, where n is the number of sides. For a 24 sided shape this gives (2 x 24) - 4 = 44 right angles = 3960°.

It is: 360/24 = 15 sides

We know that the sum of the exterior angles of a regular polygon is 360°. Since the exterior angle is 24°, then 24°n = 360° divide both sides by 24°; n = 15 Thus a 15-sided regular polygon has an exterior angle of 24°. If you don't remember the above fact, you can work in this way: If the exterior angle is 24°, then the angle of polygon will be 156° (180 - 24). Since the sum of the angle of the polygon is equal to (n - 2)180°, then we have: 156° n = (n - 2)180° 156° n = 180°n - 360° subtract 156°n and add 360° to both sides; 360° = 24°n divide by 24° to both sides; 15 = n

Any value you like, between 0 and 360 degrees. And the word is exterior, not extirior. The sum of the exterior angles of a polygon is 360 degrees, however many sides it has. If the polygon is regular (and only then) the value of each angle can be calculated. In the case of a 24-gon each would be 360/24 = 15 degrees.

There can be no such polygon. The sum of exterior angles of any polygon is 360 degrees. If the sum of the exterior angles is 15 times the sum of the interior angles, then the sum of the interior angles must be 360/15 = 24 degrees. Now, the sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 24 That is, (n-2) = 24/180 = 0.133... and so n = 2.133...sides But n must be an integer and it must be greater than or equal to 3.