No multiples of 2 are factors of 3.
There is no such number.
all numbers that are multiples of 4 have 2 as factor
52 and 56 are multiples of 4 and have 1, 2 and 4 in common. 54 and 57 are multiples of 3 and have 1 and 3 in common.
They are 33 and any of its multiples
First, factor: 16 = 2*2*2*2 18 = 2*3*3 Multiply the factors (only count overlapping ones once) to find the least common multiple (LCM) LCM = 2*2*2*2*3*3 = 144 The multiples of 16 and 18 are {144, 288, 432, 576...}
Example: 30 and 42 Factor them. 2 x 3 x 5 = 30 2 x 3 x 7 = 42 Select the highest amount of each factor. 2 x 3 x 5 x 7 = 210, the LCM Multiples of 210 will all be common multiples of 30 and 42 and can be found by multiplying 210 by successive counting numbers. 210 x 1 = 210 210 x 2 = 420 210 x 3 = 630 and so on.
Multiples of 6.
Multiples of 30
No, 22 = 2 x 11. See discussion for more info about multiples of 3 (or 3 as a factor).
All multiples of 3 are factors of something.
You make make a factor tree to solve this:24 = 6 * 4 = 3 * 2 * 2 * 2Therefore, the factors of 24 which are multiples of 3 are 3, and 3*2 = 6, and 3*2*2 = 12
Multiples of 3.
Because 3 is a factor of 6.
Two and three are relatively prime, or coprime. That means that they have no smaller number, or factor, in common. So, the multiples of both numbers are the multiples of the product of the two, or the multiples of six.
2 x 2 x 2 x 3 x 5 = 120
Multiples of 840
Yes they are - since 3 is a factor of 6.
all numbers that are multiples of 4 have 2 as factor