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Why a small departure from 45 degree landing angle can reduce the horizontal range?
Wiki User
∙ 11y ago
The range of a projectile on level ground, when air resistance is ignored, is
d = v2*sin(2x)/g where
v is the intial velocity of the projectile,
x is the angle above the horizontal at which the projectile is launched
and
g is the acceleration due to the earth's gravity.
This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
The range of a projectile on level ground, when air resistance is ignored, is
d = v2*sin(2x)/g where
v is the intial velocity of the projectile,
x is the angle above the horizontal at which the projectile is launched
and
g is the acceleration due to the earth's gravity.
This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
The range of a projectile on level ground, when air resistance is ignored, is
d = v2*sin(2x)/g where
v is the intial velocity of the projectile,
x is the angle above the horizontal at which the projectile is launched
and
g is the acceleration due to the earth's gravity.
This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
The range of a projectile on level ground, when air resistance is ignored, is
d = v2*sin(2x)/g where
v is the intial velocity of the projectile,
x is the angle above the horizontal at which the projectile is launched
and
g is the acceleration due to the earth's gravity.
This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
Wiki User
∙ 11y ago
Wiki User
∙ 11y agoThe range of a projectile on level ground, when air resistance is ignored, is
d = v2*sin(2x)/g where
v is the intial velocity of the projectile,
x is the angle above the horizontal at which the projectile is launched
and
g is the acceleration due to the earth's gravity.
This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
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