Write a program to calculate the sum of n numbers using array?

Answer 1

int myArray[N]; //where N is a constant

int mySum = 0;

...

for (int arrayIndex1 = 0; arrayIndex1 < N; arrayIndex1++)

{

cin >> myArray[arrayIndex1];

}

...

for (int int arrayIndex2 = 0; arrayIndex2 < N; arrayIndex2++)

{

mySum +=myArray[arrayIndex2];

}

...

Answer 2

//Sum of n numbers.

#include

void main()

{

int a[],n,sum=0;

printf("enter total number of numbers you want to sum up");

scanf("%d",&n);

printf("Enter the numbers one by one");

for(int i=0;i

{

scanf("%d",&a[i]);

}

for(int j=0;j

{

sum+=a[j];

}

printf("The Sum of %d numbers is = %d",n,sum);

}

IF YOU MEANT "SUM OF FIRST N NUMBERS THEN THIS IS THE PROGRAM IN c"

#include

main()

{

int n;

printf (" enter the number upto which you want the sum : ");

scanf ("%d",&n);

int res;

res = (n * (n+1)/2);

printf ("sum of first %d numbers is %d", n,res);

getch();

}

Answer 3

Use a valarray rather than an array. A valarray is an array specifically tailored for numeric values, and provides a valarray::sum() method to sum the elements.

#include<iostream>

#include<valarray>

#include<cassert>

int main()

{

std::valarray<int> a {4, 8, 15, 16, 23, 42};

assert (a.sum() 108);

}

Answer 4

If the numbers are consecutive, use a for loop, and just add the counter variable. The following example (Java language) will add the numbers 1, 2, ... 100:

int sum = 0;
for (int i = 1; i <= 100; i++)
sum += i;

If you want to add numbers in an array, loop through the array elements. I will assume the array already exists:

int sum = 0;
for (int i = 1; i <= 100; i++)
sum += myArray[i];

Answer 5

In Java: // This program adds all numbers in the array int sum = 0; for (int i = 0; i < myArray.length(); i++) { sum += myArray[i]; }

In Java: // This program adds all numbers in the array int sum = 0; for (int i = 0; i < myArray.length(); i++) { sum += myArray[i]; }

In Java: // This program adds all numbers in the array int sum = 0; for (int i = 0; i < myArray.length(); i++) { sum += myArray[i]; }

In Java: // This program adds all numbers in the array int sum = 0; for (int i = 0; i < myArray.length(); i++) { sum += myArray[i]; }

Answer 6

The answer is with using recursion.....]

the code follows

import java.io.*;

import java.util.Scanner;

// This program computes sum 1 to N numbers using recursion

public class SumRecursion

{

public static void main(String[] args)

{

System.out.println("Enter N");

try

{

BufferedReader br = new BufferedReader( new InputStreamReader(System.in));

int number= Integer.parseInt(br.readLine()); // reads number as a string from keyboard and converts to number

/* Scanner sc = new Scanner(System.in); // We can also use this lines for getting N

int number = sc.nextInt(); */

int sum = sumR(number); // calling sumR function

System.out.println("Sum of " + number + " Numbers using Recursion is : " + sum);

}

catch (Exception e)

{

System.out.println ("Give Proper Input i.e. Enter Numeric value only and with in range");

}

}

// Computes a Sum of N numbers by recursion.

public static int sumR(int num)

{

int sum;

if(num==1) return(1) ; else sum=num + sumR(num-1); // function calls itself

return sum;

}

}

Answer 7

write algorithem to find the sum of given n number

Answer 8

In Java: // This program adds all numbers in the array int sum = 0; for (int i = 0; i < myArray.length(); i++) { sum += myArray[i]; }

Answer 9

NA