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12 x 8 = 64

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Melissa Rogers

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3y ago

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What is the equation written in standard form of 2X - y - 8 equals 0?

2X - y - 8 = 0the standard form of the equation is y = mx + chere you have to write the given equation in the standard form as in the form of y = mx + c2X - y - 8 = 0 - y -8 = -2x-y = -2x +8y = 2x -8so the standard form of the given equation is y = 2x - 8


If the coefficient 2 is placed in front of the product tetraiodine nonaoxide (I4O9) then how many atoms of each element must be accounted for on the other side of the equation?

If the coefficient 2 is placed in front of tetraiodine nonaoxide (I₄O₉), the formula becomes 2 I₄O₉. This means there are 8 iodine (I) atoms and 18 oxygen (O) atoms on the left side of the equation. Therefore, the other side of the equation must also account for 8 iodine atoms and 18 oxygen atoms to balance the equation.


What is the volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. What does the pressure of the gas do?

The gas pressure increases by a factor of 8. The relevant equation is pV = nRT. Since nothing on the right side of this equation changes, the product on the left side must remain constant. The volume is stated to decrease by a factor of 4/0.5 or 8; therefore the pressure must increase by the same factor.


Can a chemical equation have different coefficients on either side of the equation?

yes. the goal of a balanced equation is to have the same amount of atoms of an element on both sides. Ex. if the product side have a total of 8 oxygen atoms than the reactant side should have a total of 8 oxygen atoms Ex. MgSO4 + 2 H20 --> Mg(OH)2 + H2SO4 1 Mg atom on both sides 1 S atom on both sides 4 H atoms on both sides 6 O atoms on both sides


When an isotope undergoes beta decay which of the following does NOT change?

The answer is c., The mass number.Check step 5 below.Let's walk through balancing a nuclear equation involving beta decay. We are going to figure out a balanced equation for thorium-2341. You will need to find the atomic number for thorium (234) and the chemical symbol (Th).2. We know that this is undergoing beta decay, so one of the products will be decaying.3. We now need to set up the equation. We are going to use the followingZ=the atomic number of the product isotopeA=the mass number of the product isotopeX-the chemical symbol of the product isotope4. Let's now set up the equation:5. We will now figure out the mass number (A) of the product. We will do this as follows:234=mass number of thorium0=mass number of beta particle234=A+0234=A6. We will now figure out the atomic number (Z) of the product. We will do this as follows:90=Z+(-1) (complete this by subtracting -1 to each side of the equation)90-(-1)=Z+(-1) - (-1)91=Z7. So far we have this:8. Now, we need to figure out the product element (X). We do this by looking for the element that has an atomic number of 91. This is protactinium (Pa). So, the complete balanced equation will look like this:You have balanced an equation using beta decay.