18. Two of spades through ten of spades, and two of clubs through ten of clubs.
There are 26 black cards in a standard pack of cards, 13 spades and 13 clubs.
A standard deck of cards (not counting jokers) has 52 cards. Half (clubs and spades) are black. That's 26 cards.
There are 26 black cards in a deck.
There are 52 cards in a standard deck, half of which are red, and half are black.
There are 13 cards in each suit.
There are 5!/(2!*3!) = 10 ways.
325.
2,600.
4
The number of selections of 3 cards that can be made from 12 different cards (it does not matter if they are face cards or not) is the number of combinations of 12 things taken three at a time. In this case it is (12! - 9!) / 3! which is 220.
Three combinations: 23, 24 and 34
The probability of drawing three black cards from a standard pack depends on:whether the cards are drawn at random,whether or not the drawn cards are replaced before the next card is drawn,whether the probability that is required is that three black cards are drawn after however many draws, or that three black cards are drawn in a sequence at some stage - but not necessarily the first three, or that the first three cards cards that are drawn are black.There is no information on any of these and so it is not possible to be certain about the answer.The probability of drawing three black cards, in three random draws - without replacement - from a standard deck, is 0.1176 approx.
An infinite number of combinations of fractions can be aded together to equal three fourths.
The probability of drawing three black cards one at a time with replacement from a standard deck of 52 cards is 1/3x1/2x26/52, which is 0.833.
there are 10 possibilities for the first spot, 9 for the second, 8 for the third 10x9x8=720 combinations
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
There are only four combinations but there are 8 permutations.
Six * * * * * No, that is the number of PERMUTATIONS (not combinations). With 3 numbers, the number of combinations, including the null combination, is 23 = 8. With the three numbers 1,2 and 3, these would be {None of them}, {1), {2), {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}.
7 + 8 + 9
There are 18*17*16/6 = 816 of them!
If the question concerned the number of combinations of three different coins, the answer is 23-1 = 7. If the coins are a,b,and c, the combinations are a, b, c, ab, ac, bc, abc. If two of the coins are the same there are only 5 combinations and if all three are the same there are 3.