-28.12 deg F
334 ml is equal to 0.334 liters.
.334
167 multiplied by 2 is 334.
234+100=334
334mL = 0.334 liters.
To melt 1 gram of ice at 0°C, it requires 334 joules of energy. So for g grams of ice, the energy needed would be g multiplied by 334 joules.
33,400 grams in one kg
334 metres is very much bigger.
The heat lost by water at 0 degrees Celsius to change to ice is equal to the heat of fusion of water, which is about 334 joules per gram. So, for 2 grams of water, the heat loss would be 2 * 334 = 668 joules.
To melt 25g of ice at 0 degrees Celsius, you need 334 J/g of energy (latent heat of fusion of ice). To convert this to kilojoules: 334 J/g * 25g = 8350 J = 8.35 kJ.
To freeze liquid water at 0 degrees Celsius, you need to remove 334 J/g of energy. To cool it from 0 degrees Celsius to -20 degrees Celsius, you need to remove an additional 80 J/g. Therefore, for 75g of water, the total energy released would be 75g * (334 J/g + 80 J/g) = 33,200 J.
No because 1 kilometer equals 1000 meters