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Q: - If 3X - 1 equals what is the value of X2 plus X?

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x=-11

3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18

x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.

-2

x = 2

3x-1=11 3x = 12 x = 4 Then, x^2 +x = 20.

x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}

x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0

If 3x - 1 = 11, then x = 4, but this value of x does not satisfy x2 = x, because x2 = x is only true if x equals 0 or 1.

3x-1 = 11 3x = 11+1 = 12 x = 12/3 = 4 Therefore: x2 + 2 = 16 + 2 = 18

The answer would be 3x if 'X2' is '2x', but if 'X2' is x2, then the total answer would be x2 + x.

x2 + 3px + p = 0 x2 + p(3x + 1) = 0 p(3x+1) = -x2 p = -x2/(3x+1) So p can have any value at all. In fact, around x = -1/3, p goes asymptotically to + and - infinity.

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