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Q: How do you solve x2 plus 3x plus 3 0?

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x2+3x+1 = 0 Using the quadratic equation formula gives you: (x+2.618033989)(x+0.3819660113) = 0 So: x = -2.618033989 or x = -0.3819660113

x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}

x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0

-2

X2 + 3X = 0X(X + 3) = 0--------------------X is the greatest common factorso,X = 0----------orX = - 3----------- assuming you might want to solve this type of problem some day

Yes:- x2+3x+2 = 30 X2+3x+2-30 = 0 x2+3x-28 = 0 (x-4)(x+7) = 0 x = 4 or x = -7

x2+3x+2=0 (x+2)(x+1)=0 x=-2 or -1

x2 + 3px + p = 0 x2 + p(3x + 1) = 0 p(3x+1) = -x2 p = -x2/(3x+1) So p can have any value at all. In fact, around x = -1/3, p goes asymptotically to + and - infinity.

x^2+3x-18=0 (x+6)(x-3)=0

(x-1)(x+4)

x2 + 3x - 7 = 5x + 8; thus, x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15 = (x - 5)(x + 3) = 0. Therefore the solution is x = 5 or -3.

x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6

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