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Sorry, I don't think the question makes sense the way it appears here. My understanding is you have prepared a 0.1565M solution by mixing an unknown concentration with the same amount of water?

If this is the case, you multiply the end solution by 2 because you diluted it 2 fold (1 part unknown in 1 part water)

So the original would be 0.3112M

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Q: 0.1556M stock sol'n of b has been prepared concentration of B were prepared sol'n b3using a beaker- 50ml ml of stock sol'n- 50ml ml of distilled H2O Calculate the concentration of b in sol'n 3?
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