It is the intercept: the value that y takes when x = 0
x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0
A=0 b=0 c=0
The value of c/30 that equals 12 is 12 . In order to make that value, 'c' must be 360 .
A=B , A-B=B-B , A-B =0 B=C , B-B=C-B, 0=C-B So A-B=0 but also C-B=0 A-B=C-B ...add +b ...A-B+B=C-B+B , A=C
Because the value of C equals 13
0.04c + 1.6 = 00.04c = -1.6c = -40
the value of 0 is '1'.
It depends on the value of c. If c = 0 then 0-0+5 = 5 If c = 1 then 1-2+5 = 4 If c = 2 then 4-4+5 = 5 and so on.
that depends on what the value of c is.
If B=0, then the graph does not depend on the value of y. This is a vertical line at x = C/A
The result is 7.
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
For the equation x2- 10x - k equals 0, you can solve this by knowing that if there is only one solution then the discriminant b2 - 4ac must be equal to 0. In this equation, a is 1, b is 10 and c is k This equation becomes 100 - 4k equals 0, and k is 25.
x = -c/(a+b), provided a+b is not 0
Two: one is 0, the other is -b/a ax2 + bx + c = 0, but c = 0 ⇒ ax2 + bx + 0 = 0 ⇒ ax2 + bx = 0 ⇒ x(ax + b) = 0 ⇒ x = 0 or (ax + b) = 0 ⇒ x = -b/a
c is any constant value
0 Celsius equals 32 Fahrenheit
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
Because there is no way to define the divisors, the equations cannot be evaluated.
well the only answer i can so far come up with is: a=1 b= -1 c=0 so then (a+b)=(c*c)=(a*c) ...............(0)=(0)=(0) ......................0 ok if that is what your looking for Great! just know that i am not a math wiz. :)
To get rid of c from both sides you divide by c so c can't be 0