the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
The x in y=mx+b is the independent variable. You could solve for x, making this a function of y, with simple algebra. y = mx + b y - b = mx (y-b)/m = x
When the equation is in the form "y = mx + c" the intercept is given by 'c' (and the gradient by 'm'): 3x + 3y = 9 ⇒ x + y = 3 ⇒ y = -x + 3 ⇒ Intercept is 3 (And the gradient is -1)
No, y=x^2 + 2 is a quadratic equation. A linear equation is one in the form y=mx+b. A quadratic has a form y=ax^2+bx+c.
It's 2. your equation is y=mx+b, so the gradient, or slope, is the "m" in the equation.
There is no difference; it is a matter of choice and convention as to what letter is used.
in the equation: y=mx+b , the y-intercept is represented by "b".
well, m is the slope and c is the y-intercept
That is the standard equation to graph a line.
c is any constant value
same thing. but its easy to change y=b+mx to y=mx+b
Yes, with slope m and y-intercept = (0,c).
slope = -4 for y=mx+c, slope=m, y intercept=c
y = mx + b y - mx = b
Just subtract y from both sides. 'm' becomes 'A', 'b' becomes 'C' and 'B' will be equal to one.
yes
b = y - mx.