1.12 x 12 = 13.44, so 1.12 km x 12 = 13.44 km
112
12/112 x 100 = 10.714285 recurring (that is, 10.714285714...) or 10 5/7 percent.
Let's denote the smallest odd integer as x. The next three consecutive odd integers would then be x+2, x+4, and x+6. The sum of these four integers is x + (x+2) + (x+4) + (x+6) = 4x + 12. Given that the sum is 112, we have 4x + 12 = 112. Solving for x, we get x = 25. Therefore, the greatest of the four integers is x + 6 = 25 + 6 = 31.
28/3 x 12 = 112
112 x 5 = 560
112 x 615 = 68,880
112 x 2 = 224
1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14 = 112 and 56 + 56 = 112
112 = 1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14
2 x 2 x 2 x 2 x 7 = 112
112 = 1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14, 14 x 8, 16 x 7, 28 x 4, 56 x 2, 112 x 1
112 = 1 x 112, 2 x 56, 4 x 28, 7 x 16, 8 x 14, 14 x 8, 16 x 7, 28 x 4, 56 x 2, 112 x 1.