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What is the limiting reactant in 2Al plus 3Cl2 equals 2AlCl3?
moles of Al=4.40 g/26.9815 g/mol=0.163 moles cl2=15.4g/70.906g/mol=0.217 the ratio is 2:3 cl2 is the limiting reagent
How many milligrams of sodium make one gram of salt?
Formula for table salt = NaCl 1.00 g = 1.00 / 58.45 mol = 1.71 x 10-2 mol Mole Na required = 1.71 x 10-2 mol Mass of Na = 1.71 x 10-2 mol x 23.0 g /mol = 0.393 g = 393 mg
Consider the equation 2a plus b--a2b if you mix 1.0 mol of a and 1.0 mol of b how many moles of a2b can be produced?
Because it takes 2a to make 1mol of a2b, the ratio is 1mol a2b/2mol a. If you only have 1.0 mol of a to react, then 1mol a x (1mol a2b/2 mol a)= 0.5 mol of a2b Because it takes 1 mol of b to make 1 mole of a2b, the ratio is 1mol a2b/1mol b. So, 1.0 mol b x (1mol a2b/1mol b)= 1.0 mol of a2b. Since you run out of a to react with b, a is the limiting reagent meaning that you can only produce 0.5 mol of a2b even though you have an excess amount of b. So, only 0.5 mol of a2b can be produced.
What is faraday constant?
•96485 coulomb/mol of electrons (for J) •23054 C/mol (for Cal) •23.054 C/mol (for kCal) •
Is the concentration of H plus in solution given the OH equals 2.54 x 10-4?
[H+] = Kw / [OH-] = 1.0*10-14 / 2.5*10-4 = 4.0*10-11 mol/L
How do you convert mmol to milliters?
1 mol = 103 mmol Conversely, 1 mmol = 10-3 mol For example: 25 mol x 103 mmol/1 mol = 25000 mmol and, 3.2 mmol x 10-3 mol/1 mmol = 0.0032 mol
What is 25 mmol converted to mol?
25 mmol equates to 0.025 mol
How many mmol are in 3.5 mol?
3.5 mol x (1000mmol/1mol) = 3500mmol
2.55 mmol to moles?
1000 mmol = 1 mol. So, what you do is 2.55mmol*(1mol/1000mmol). The mmol's cancel and you are left with mol. The "m" is a metric prefix. So, 1000mN = 1N just like 1000mmol = 1mol.
Convert mmol to mol?
1 mEq=1 mmol/valence e.g.For sodium, 1 mEq=1mmol/1 (valence of sodium=1) means, 1 mmol sodium=1 mEq of sodium take for calcium,valence=2 1 1 mEq of calcium=1mmol/2=0.5 mmol of calcium
How many grams are equal to 450 milligrams?
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
What mass of NaHCO3 would be needed to neutralize a spill consisting of 12.5 mL of 5.0 M HCl?
12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3
What volume of 18.0 m sulfuric acid is required to prepare 19.6 L of 0.126 m H2SO4?
Using V * M = constant at dilution = amount of H2SO4 [mol] in both of the solutionsV= volume [L] of the solutionM= molarity [mol/L] of the solutionSo: V *18.0 = 24.9 * 0.195 gives V = ( 24.9 * 0.195 ) / 18.0 = 0.270 L
How many grams of alcl3 are produced from with 8.0 moles of al2o3. 6cl2 plus 2al2o3 equals 3o2 plus 4alcl3 equals?
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
What Substance Require The Most Heat To Melt 1 Kg Of The Substance?
Carbon: 105 kJ/mol = 105 (kJ/mol) / 0.012(kg/mol) = 8750 kJ/kg Carbon
What is the final concentration if 100 mL of water is added to 25.0 mL of 6.0 M NaCl?
We must first figure out the amount of NaCl in moles: M = mol/L = mmol/mL 6 = mmol/25 mL 150 mmol NaCl Now divide by the total volume to get the final concentration: 150 mmol/100 mL = 1.5 M NaCl
If 25.5mg of oxalic acid dihydrate are dissolved in 1.00 ml of solution what is the molarity of the resulting solution?
0.063 g of oxalic acid * (1 mol H2C204*2H2O / 126.07 g) = 0.0004997 mol H2C2O4*2H2O 0.0004997 mol H2C204 / 0.250 L = 0.001999 M of H2C2O4
