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moles of Al=4.40 g/26.9815 g/mol=0.163

moles cl2=15.4g/70.906g/mol=0.217

the ratio is 2:3

cl2 is the limiting reagent

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Q: What is the limiting reactant in 2Al plus 3Cl2 equals 2AlCl3?
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Related questions

How can you balance 2Al plus Cl ---- 2AlCl3?

2Al + 3Cl2 ---> 2AlCl3


In the chemical reaction 2AlCl3 equals 2Al plus 3Cl2 the substances Al and Cl2 are called what?

In the chemical reaction 2AlCl3 equals 2Al plus 3Cl2, the substances Al and Cl2 are called products. They are formed as a result of the chemical reaction between aluminum chloride (AlCl3).


What is the equation for aluminum bromide plus chlorine yield aluminum chloride plus bromine?

The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2.


Balanced Equation for aluminum and hydrochloric acid?

2Al + 3Cl2 -> 2AlCl3


What is the maximum mass of aluminum chloride that can be formed when reacting 25.0 g of aluminum with 30.0 g of chlorine?

To find the limiting reactant, calculate the moles of each reactant using their molar masses. The balanced chemical equation is 2Al + 3Cl2 → 2AlCl3, so the stoichiometry ratio is 2:3. Aluminum is the limiting reactant as it forms fewer moles of product. Thus, all 25.0 g of aluminum will react with 112.5 g of chlorine to form 67.5 g of aluminum chloride.


What is the chemical formula for aluminium bromide plus chlorine yield aluminium chloride plus bromine?

The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 → 2AlCl3 + 3Br2.


How many moles of product are formed in the reaction 2Al plus 3Cl2 yields to 2AlCl3?

3


What is the maximum mass of aluminum chloride that can be formed when reacting 28.0g of aluminum with 33.0g of chlorine?

The balanced chemical equation for the reaction between aluminum and chlorine is 2Al + 3Cl2 -> 2AlCl3. To find the limiting reactant, calculate the moles of each reactant using their molar masses. The reactant that produces the least amount of product is the limiting reactant. In this case, determine that with 28.0g of aluminum and 33.0g of chlorine, aluminum is the limiting reactant. Use the stoichiometry of the balanced equation to find the maximum mass of aluminum chloride that can be formed.


What is the equation for Aluminum chloride is formed from its elements?

The equation for the formation of aluminum chloride from its elements is: 2Al(s) + 3Cl2(g) -> 2AlCl3(s)


What is the formula when aluminum metal reacts with chlorine gas to form solid aluminum chloride?

The balanced chemical equation for the reaction between aluminum metal and chlorine gas to form solid aluminum chloride is: 2Al (s) + 3Cl2 (g) -> 2AlCl3 (s)


What is the balance equation for solid aluminum chloride is formed when elemental aluminum is burned in chlorine gas?

2Al(s) + 3Cl2(g) -> 2AlCl3(s)


What is the balanced chemical equasion for aluminum metal burning in chlorine gas to produce aluminum chloride?

The balanced chemical equation for aluminum metal burning in chlorine gas to produce aluminum chloride is: 2Al(s) + 3Cl2(g) -> 2AlCl3(s)