=(12^5)+(12^4)+(02^3)+(12^2)+(02^1)+(12^0)
=32+16+0+4+0+1
=53 base 10
11210
The sequence "110101" is a binary number, which is a base-2 numeral system that uses only two digits: 0 and 1. In decimal (base-10), this binary number converts to 53. Each digit represents a power of 2, starting from the rightmost digit, which represents (2^0), and moving left. Therefore, it can be calculated as (1 \times 2^5 + 1 \times 2^4 + 0 \times 2^3 + 1 \times 2^2 + 0 \times 2^1 + 1 \times 2^0).
It is 110101, exactly as in the question. A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right.
It is (CX)CI meaning 1,000*110+101 = 110,101
base-2 : 111 = 7(base-10) base-3: 222 = 26(base-10) base-4: 333 = 33(base-10) base-5: 444 = 124(base-10) base-6: 555 = 215(base-10) base-7: 666 = 342(base-10) base-8: 777 = 511(base-10) base-9: 888 = 728(base-10) base-10: 999 = 999(base-10) base-11: AAA = 1241(base-10) base-12: BBB = 1727(base-10) base-13: CCC = 2196(base-10) base-14: DDD = 2743(base-10) base-15: EEE = 3374(base-10) base-16: FFF = 4095(base-10) In short, base-n: n cubed - 1(base-10)
log(e)100 = log(10)100 / log(10)e = log(10)100 / log(10) 2.71828.... = 2/ 0.43429448... = 4.605170186..... (The answer). NB Note the change of log base to '10' However, on a calculator type in ;- 'ln' (NOT log). '100' '=' The answer shown os 4.605....
A counting base of 10 is a decimal base.
The base is 10.
10 base 6 equals 6 base 10
( 1010 )2 = ( 10 )10
1010 base 2 = 10 base 10 1010 base 10 = 11 1111 0010 base 2
503 base 10 = 767 base 8 503 base 8 = 323 base 10