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What size circuit breaker is used for a 10000 watt single phase cooler with 240 volts?
The equation for amperage is Amps = Watts/Volts = 10000/240 = 41.6 amps. It is not stated if this is a motor load or not. If it is a motor load then the feeder has to be rated at 125% x 41.6 = 52 amp wire. Also if it is a motor load then the breaker will have to be 250% x 41.6 = 104 amps. A 100 amp breaker will work and still be within the electrical code ruling. Otherwise for 41.6 amps a 50 amp breaker will be sufficient.
Which wire used single phase 240v 6.5kw load?
I = W/E. Amps = Watts/Volts = 6500/240 = 27 amps. A #10 copper conductor with an insulation factor of 90 degrees C is rated at 30 amps. If the load is continuous the conductor can only be loaded to 80% of its capacity. 30 x 80% = 24 amps which is too low for your load. Move to the next size wire which is a #8 which is rated at 40 amps x 80% = 32 amps. As long as no long distance runs are involved this wire size will work well.
What size portable generator is good for a 2 story home?
Generators are sized by the electrical load that is to be applied to it. If you want to pick up the total house load then a 25 to 30 kW generator will do the job. At 240 volts this will give you just over 100 amps to work with. Amps = Watts/Volts.
Specifications carpigiani electrical LB-502?
208-230 Volts 1/3 Phase 60 Cycles Breaker Size 50 / 40 Amps Run Amps 39/31
Is 6-3 wire sufficent for wiring 15k standby generator?
The wire size is based on the amperage to the load. This is the quick estimate for amps when kilowatts are known, Amps = Watts/Voltage. As you can see the value of the voltage that the generator produces is needed. A #6 copper wire with 90 degree C insulation is rated at 65 amps. The following are exact formula for amps when kilowatts are known. This is a formula for single phase generation, Amps = kW x 1000/Volts x pf. The three phase formula is, Amps = kW x 1000/1.73 x Volts x pf. pf = power factor.
What size motor overloads to put on a 3 phase motor.i how to go about to calculate this. its a 5 HP Motor208-230 volt12.9amp at 208SF1.25 SFA 16.1. the motor is a outdoor motor replacing and old o?
5 HP is equal to 3.7 KW. 415 Volts 3 phase 50 hz system takes 6.29 amps. Same 3.7 KW motor with 230 volts, single phase 50 hz takes 18.9 amps. Same 3.7 kw motor with 230 volts three phase 50 Hz takes 11.1 amps. These are full load current with 0.85 assumed power factor. To arrive at over load, you may 5 to10% over load and set the over load setting.
What size wire do you need for 650 watts?
To answer this question a voltage needs to be stated. Wire is sized by the amount of amperage the load takes. W = Amps x Volts. Amps = 650/ volts.
What size circuit breaker is used for a 10000 watt single phase cooler with 240 volts?
The equation for amperage is Amps = Watts/Volts = 10000/240 = 41.6 amps. It is not stated if this is a motor load or not. If it is a motor load then the feeder has to be rated at 125% x 41.6 = 52 amp wire. Also if it is a motor load then the breaker will have to be 250% x 41.6 = 104 amps. A 100 amp breaker will work and still be within the electrical code ruling. Otherwise for 41.6 amps a 50 amp breaker will be sufficient.
What size of circuit breaker do you use for 25amperes induction motor?
Read the specification plate on the motor to determine the amount of current that the motor uses, as well as the voltage and phase. Most likely, it will be a 3 phase motor, so you can't simply connect it to your house wiring, but without sufficient information, it is impossible to tell you all of the specifics. <<>> The code book rates the amperage of a three phase 40 HP motor by different voltages. at 200 volts - 120 amps, 230 volts - 104 amps, 460 volts - 52 amps and 575 volts - 52 amps. A breaker for a motor has to be sized to 250% of the motors full load amps. Also the wire size for a motor has to be 125% of the motor full load amps.
Which wire used single phase 240v 6.5kw load?
I = W/E. Amps = Watts/Volts = 6500/240 = 27 amps. A #10 copper conductor with an insulation factor of 90 degrees C is rated at 30 amps. If the load is continuous the conductor can only be loaded to 80% of its capacity. 30 x 80% = 24 amps which is too low for your load. Move to the next size wire which is a #8 which is rated at 40 amps x 80% = 32 amps. As long as no long distance runs are involved this wire size will work well.
How many amp service do you need to handle 450 volts?
This depends solely on the load you might need a 15 amp service or a 1200 amp service. To find out look at the installation instructions and it will tell you what size the service supply needs to be. Watts = Amps times Volts Amps = Watts divided by Volts Volts = Amps divided by Watts Example 1500 Watt unit will pull 12.5 Amps at 120 Volts or 1500 Watt unit will pull 3.26 Amps at 460 volts or A 460 volt unit rated for 34 amps will be using 15.64 kWh or 15,640 Watts Also the higher the voltage, the lower the Amperage, however, the wattage will stay the same <<>> The question is asking about two different values. Voltage is an insulation value whereas amperage is a conductor size. The basic insulation values are 300, 600 and 1000 volts. In the question on this service, a insulation factor of 600 volts will be used for the conductors. The amperage of a service is based on the connected load that needs to be supplied. The load can be an individual load or as in a distribution panel a variety of loads. At 460 volts, the service can be either a three phase service or a single phase service. Once the load amperage has been established, the wire size for the service can be calculated. Once the wire has been sized, the breaker used to protect the wire from being overloaded will be calculated.
What minimum fuse rating is needed for a 12 volt circuit when using one 48 watt bulb?
The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.
Which wire used single phase 240v 6.5kw load used in poultry?
I = W/E. Amps = Watts/Volts = 6500/240 = 27 amps. A #10 copper conductor with an insulation factor of 90 degrees C is rated at 30 amps. If the load is continuous the conductor can only be loaded to 80% of its capacity. 30 x 80% = 24 amps which is too low for your load. Move to the next size wire which is a #8 which is rated at 40 amps x 80% = 32 amps. As long as no long distance runs are involved this wire size will work well.
What size wire do you need for a 208 volt 3 phase load that draws 10.5 amps?
The size of conductor needed will be a #14. It should be copper and have an insulation factor of 90 degrees C. The fact that it is a three phase load does not enter into the calculation of the wire size.
What size diesel generator would you need if there was a power outage?
The size of the generator is based on the size of the load you want to supply. Size up the load in watts or amps along with what phase (single or three) and voltage that the load requires. These are needed to give a complete answer.
What size portable generator is good for a 2 story home?
Generators are sized by the electrical load that is to be applied to it. If you want to pick up the total house load then a 25 to 30 kW generator will do the job. At 240 volts this will give you just over 100 amps to work with. Amps = Watts/Volts.
What size wire to carry 8 amps at 120 volts?
A # 14 copper conductor will be fine to carry 8 amps at 120 volts. This size conductor is rated at 15 amps.
